ITU在BT.601中规定，wr=0.299，wb=0.114，wg=1-wb-wr=0.587。

所以可得变换矩阵

$\left(\begin{array}{l} \boldsymbol{Y} \\ C_{b} \\ C_{r} \end{array}\right)=\left(\begin{array}{rrr} 0.299 & 0.587 & 0.114 \\ -0.169 & -0.331 & 0.500 \\ 0.500 & -0.419 & -0.081 \end{array}\right) \cdot\left(\begin{array}{l} R \\ G \\ B \end{array}\right)$

$\left(\begin{array}{l} R \\ G \\ B \end{array}\right)=\left(\begin{array}{rrr} 1.000 & 0.000 & 1.403 \\ 1.000 & -0.344 & -0.714 \\ 1.000 & 1.773 & 0.000 \end{array}\right) \cdot\left(\begin{array}{l} Y \\ C_{b} \\ C_{r} \end{array}\right)$

由于计算过程中可能出现负数，所以需要进行取绝对值
Y = 0.299 R + 0.587 G + 0.114 B
Cb = -0.1687 R - 0.3313 G + 0.5 B + 128
Cr = 0.5 R - 0.4187 G - 0.0813 B + 128
R = Y + 1.402 (Cr-128)
G= Y - 0.34414 (Cb-128) - 0.71414 (Cr-128)
B= Y + 1.772 (Cb-128)